In the following electrochemical cell `:`
`Zn|Zn^(2+)||H^(o+)|(H_(2))Pt`
`E_(cell)=E^(c-)._(cell).` This will be when

Options

A. `[Zn^(2+)]=[H^(o+)]=1M` and `p_(H_(2))=1atm`
B. `[Zn^(2+)]=0.01M,[H^(o+)]=0.1M,` and `p_(H_(2))=1atm`
C. `[Zn^(2+)]=1M,[H^(o+)]=0.1M,` and `p_(H_(2))=1atm`
D. None of the above.

Answer

a,b

Explanation

Cell reaction `: Zn(s)+2H^(o+)(aq)rarr Zn^(2+) (aq)+H_(2)(g)`
Using`:E_(cell)=E^(c-)._(cell)-(0.0591)/(2)log(Q_(cell)-(P_(H_(2))[Zn^(2+)])/([H^(o+)]^(2)))`
`implies` For `E_(cell)=E^(c-)._(cell),Q_(cell)=1.0`
`a. Q_(cell)=(1xx1)/(1^(2))=1`
`b. Q_(cell)=(1xx0.01)/((0.1)^(2))=1`
`c. Q_(cell)=(1xx1)/((0.1)^(2))=100`