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For the electrochemical cell, (M|M^(o+))...

For the electrochemical cell, `(M|M^(o+))||(X^(c-)|X)`, `E^(c-)._((M^(o+)|M))=0.44V`, and `E^(c-)._((X|X^(c-))=-0.33V`.
From this data, one can conclude that

A

`M+X rarr M^(o+)+X^(c-)` is a spontaneous reaction

B

`M^(o+)+X^(c-) rarr M+x` is the spontaneous reaction

C

`E^(c-)._(cell)=0.77V`

D

`E^(c-)._(cell)=-0.77V`

Text Solution

Verified by Experts

The correct Answer is:
b,c

`E^(c-)._(cell)=0.44-(-0.33)=0.77V`
Spontaneous reaction `:M^(o+)+X^(c-)rarr M+X`
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For the electrochemical cell, (M|M^(o+))||(X^(c-)|X),E^(c-)._((M^(o+)|M))=0.44V and E^(c-)._((X|X^(c-)))=0.334V

If E^(@)(M^(+)/M)= -0.44V and E^(@)(X/X^(-)) = 0.33V . From this data one can conclude that:

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For the electrochemicl cell, M|M^(+)||X^(-)|X E_((M^(+)//M))^(@) = 0.44 V and E_((X//X^(-)))^(@) = 0.33 V From this data one can deduce that :

For the electrochemical cell, M|M^(+) ||X^(-)|X , E_(M^(+)//M)^(@) = 0.44 V and E_(X//X^(-))^(@) = 0.33 V . From this data we can deduce that :

Given E^(c-)._(Ag^(o+)|Ag)=+0.80V,E^(c-)._(Co^(2)|Co)=-0.28V, E^(c-)._(Cu^(2+)|Cu)=+0.34V,E^(c-)._(Zn^(2+)|Zn)=-0.76V Which metal will corrode fastest ?

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