During electrolysis of aqueous `CuBr_(2)` using `Pt` electrode,

Options

A. `Br_(2)(g)` is evolved at anode
B. `Cu(s)` is deposited at cathdoe
C. `Br_(2)(g)` is evolved at anode and `H_(2)(g)` at cathode
D. `H_(2)(g)` is evolved at anode

Answer

a,b

Explanation

Aqueous `CuBr_(2):`
At cathode `:(sqrt())Cu^(2+)+2e^(-)rarr Cu,`
`E^(c-)._(Cu^(2+)|Cu)=+0.34V`
`(X)2H_(2)O+2e^(-) rarr H_(2)+2overset(c-)(O)H,` ltbr. `E^(c-)._(H_(2)O|H_(2))=-0.83V`
At anode `:(sqrt())2Br^(c-)rarr Br_(2)+2e^(-),`
`E^(c-)._(Br^(c-)|Br_(2))=-1.09V`
`(X)2H_(2)Orarr O_(2)+4H^(o+)+2e^(-), `
`E^(c-)._(H_(2)O|H_(2))=-1.23V`