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The EMF of the following cell : Cd(s)|...

The `EMF` of the following cell `:`
`Cd(s)|CdCl_(2)(0.10M)|AgCl(s)|Ag(s)` is `0.6915V` at `0^(@)C` and `0.6753V` at `25^(@)C` . The `DeltaH` of reaction in `kJ` at `25^(@)C` is

A

`-176`

B

`-234.7`

C

`123.5`

D

`-167.6`

Text Solution

Verified by Experts

The correct Answer is:
d
Use `DeltaH=nFG[T.((dE_(cell))/(dT))-E_(cell)]`
`DeltaH_(25^(@)C)=2xx96500[298xx((0.6753-0.6715)/(25-0))-0.6753]`
`=-167.67k J mol^(-1)`
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