In the following electrochemical cell `:`
`Zn|Zn^(2+)||H^(o+)|(H_(2))Pt`
`E_(cell)=E^(c-)._(cell).` This will be when

Options

A. `[Zn^(2+)]=[H^(o+)]=1M` and `p_(H_(2))1 atm`
B. `[Zn^(2+)]=0.01 M,[H^(o+)]=0.1M, `and `p_(H_(2))=1atm`
C. `[Zn^(2+)]=1m,[H^(o+)]=0.1M,` and `p_(H_(2))=0.01atm`
D. `[Zn^(2+)]=[H^(o+)]=0.1M` and `p_(H_(2))=0.1 atm`

Answer

a,b,c,d

Explanation

`E_(cell)=E^(c-)._(cell)-(0.059)/(2) log .([H^(o+)]^(2))/([Zn^(2+)]p_(H_(2)))`
Check for `([H^(o+)]^(2))/([Zn^(2+)]p_(H_(2)))=1` for `E_(cell)=E^(c-)._(cell)`
It is possible in all cases.