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The addition of a crystal of I(2) to NaB...

The addition of a crystal of `I_(2)` to `NaBr` turns the solution violet.

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The correct Answer is:
T
Because no redox reaction occur.
Since the reduction potential of `Br_(2)gt` reduction potential of `I_(2)`.
The reaction possible is `:`

Hence , a redox reactio between `Br^(c-)` and `I_(2)` is not possible and therefore violet colour of `I_(2)` appear in the solution.
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