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Analyze the generalized rate data: RX ...

Analyze the generalized rate data:
`RX + M^(ɵ) rarr` Product
`|{:("Experiment",[RX] "Substrate",[M^(ɵ)] "Attaking species","Rate"),(I,0.10 M,0.10 M,1.2 xx 10^(-4)),(II,0.20 M,0.10 M,2.4 xx 10^(-4)),(III,0.10 M,0.20 M,2.4 xx 10^(-4)),(IV,0.20 M,0.20 M,4.8 xx 10^(-4)):}|`
The value of rate constant for the give experiment data is

A

`1.2 xx 10^(-2)`

B

`1.2 xx 10^(-4)`

C

`1.2 xx 10^(-3)`

D

`2.4 xx 10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
form experimetn I and II, when the concentration of `[RX]` becomes double, rate becomes double, so order w.r.t. `(RX) = 1`.
ismilarly, form experiments II and IV, when the concentration of `M^(ɵ)` is doubled, rate also is doubled.
So order w.r.t `[M^(ɵ)] = 1`.
Hence, rate `= k[RX][M^(ɵ)]` ...(i)
So overall second order reaction.
form Eq. (i),
`1.2 xx 10^(-4) = k[0.1][0.1]`
`:. k = 1.2 xx 10^(-2)`
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