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The rate constant for the decompoistion ...

The rate constant for the decompoistion of a certain reaction is described by the equation:
`log k(s^(-1)) = 14 - (1.25 xx 10^(4) K)/(T)`
Energy of activation (in `kcal`) is

A

`57.6 kcal`

B

`1.25 xx 10^(4) kcal`

C

`14.0 kcal`

D

`14 xx 10^(4) kcal`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(a)//2.303RT = (1.25 xx 10^(4) K)/(T)`
`:. E_(a) = 1.25 xx 10^(4) xx 2.303 xx 10^(-3) kcal`
`= 57.6 kcal`
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