For the reaction: `aA + bB rarr cC+dD`
Rate `= (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt)`
The rate of formation of `SO_(3)` in the following reaction `2SO_(2) + O_(2) rarr 2SO_(3)` is `100 g min^(-1)`. Hence the rate of disappearance of `O_(2)` is

Options

A. `2 g min^(-1)`
B. `20 g min^(-1)`
C. `200 g min^(-1)`
D. `50 g min^(-1)`

Answer

B

Explanation

For the given reaction
`(-d[O_(2)])/(dt) = (1)/(2)[d[SO_(3)])/(dt)`
`(d[SO_(3)])/(dt) = 100 g min^(-1) = (100)/(80) mol min^(-1)`
`:. (-d[O_(2)])/(dt) = (1)/(2)((100)/(80)) mol min^(-1)`
`= (1)/(2) xx (100)/(80) xx 32 g min^(-1) = 20 g min^(-1)`