For the reaction: `aA + bB rarr cC+dD`
Rate `= (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt)`
In the following reaction,
`xA rarr yB`
`log.[-(d[A])/(dt)] = log.[(d[B])/(dt)] + 0.3`
where negative isgn indicates rate of disappearance of the reactant. Thus, `x:y` is:

Options

A. `1:2`
B. `2:1`
C. `3:1`
D. `3:10`

Answer

B

Explanation

`xA rarr yB`
`(-d[A])/(x dt) = (1)/(y) (d[B])/(dt)`
`log.((-d[A])/(dt)) = log.(d[B])/(dt) + log.(x)/(y)`
`:. log.((x)/(y)) = 0.3`
`:. (x)/(y) = 2`
or `x:y = 2:1`