The rate constant of a reaction is given by `k = 2.1 xx 10^(10) exp(-2700//RT)`. It means that

Options

A. `log k` versus `1//T` will be a straight line with slope `= (-2700)/(2.303 R)`
B. `log k` versus `1//T` will be straight line with intercept on `log k` axis `= log(2.1 xx 10^(10)`).
C. The number of effective colliisons are `2.1 xx 10^(10) cm^(-3) s^(-1)`.
D. Half-life of the reaction increase with increase of temperature.

Answer

A, B

Explanation

For Arrhenius equation `k = Ae^(-Ea//RT)`
`= 2.1 xx 10^(10) xx e^(-2700//RT)`
or
`log k = log A - (E_(a))/(2.303 RT) = log 2.1 xx 10^(01) - (2700)/(2.303RT)`
Plot of `log k` vs `1//T`