For the coagulation of `100 mL` of arsenious sulphite `sol,5 mL` of `1 M NaCl` is required. What is the flocculaton value of `NaCl`?

Explanation

`5mL` of `1MNaCl` contains `NaCl=(1)/(1000)xx5mol=5m mol`
Thus, `100mL` of `As_(2)S_(3)sol` require `NaCl` for complete, coagulation `=5m mol`
`:.` 1L, i.e., `1000mL` of the sol requires `NaCl` for complete, coagulation `=50m mol`
Therefore, the flocculation value of `NaCl=50`