The coagulation of `200 mL` of a positive colloid took place when `0.73 g HCl` was added to it without changing the volume much. The flocculation value of `HCl` for the colloid is
A
`36.5`
B
`100`
C
`200`
D
`150`
Text Solution
Verified by Experts
The correct Answer is:
B
`200mL` of the sol requires `0.73gHCl` Moles of `HCl=(0.73)/(36.5)mol=0.02mol=20.0mmol` Therefore, `1000mL(1L)` of the sol will require `=(20)/(200)xx1000=100m mol`
The coagulationof 200 mL of a positive sol took place when 0.73 g HCl was added to it without changing the volume much. The flocculation value of HCl for the colloid is :
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