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For the coagulation of 500mL of arseniou...

For the coagulation of `500mL` of arsenious sulphide sol, `2mL` of `1MNaCl` is required. What is the flocculation value of `NaCl` ?

A

3

B

2

C

5

D

4

Text Solution

Verified by Experts

The correct Answer is:
D

`2mL` of `1MNaCl` contains `NaCl=(2)/(1000)=2` m mol
Thus `500mL` of `As_(2)S_(3)` sol require `NaCl` for complete coagulation `=2m mol`
Hence 1 L, i.e., `1000mL` of the sol require `NaCl` for complete coagulation `=4m mol`
Therefore, flocculation value of `NaCl=4` .
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