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The coagulation of 100 mL of a colloidal...

The coagulation of `100 mL` of a colloidal solution of gold is completely prevented by the addition of `0.030 g` of it before adding `1 mL` of `10% NaCl` solution. Find out the gold number of starch?

A

4

B

8

C

3

D

9

Text Solution

Verified by Experts

The correct Answer is:
A
Haemoglobin added to `100mL` of gold sol to prevent coagulation by `1mL` of `10%NaCl` sol `=0.03g=30mg` haemoglobin required to be added to `10%NaCl` sol `=3mg` .
Therefore, gold number of haemoglobin `=3` .
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