In the decay series `._(92)U^(238)` to `._(82)Pb^(206)`, how many `alpha`-paritcles and how many `beta^(ɵ)`-particles are emitted?

Explanation

To solve the problem of determining how many alpha particles and beta particles are emitted in the decay series from Uranium-238 to Lead-206, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Initial and Final Nuclei:**
- The initial nucleus is Uranium-238, denoted as \( _{92}^{238}U \).
- The final nucleus is Lead-206, denoted as \( _{82}^{206}Pb \).

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