Home
Class 12
CHEMISTRY
If a .(92)U^(235) nucleus upon being str...

If a `._(92)U^(235)` nucleus upon being struck by a neutron changes to `._(56)Ba^(145)`, three neutrons and an unknown product. What is the unknown product?

Text Solution

Verified by Experts

The reaction can be presented as:
`._(92)U^(235) ._(0)n^(1) rarr ._(56)Ba^(145) + ._(Z)X^(A) + ._(0)n^(1)`
Equating the mass number on both sides, we get
`235 + 1 = 145 + A + 3 xx 1`
`:. A = 88 =` Atomic mass of `X` Atom
Similarly equating atomic numbers on both sides, we get
`:. 92 + 0 = 56 + Z + 3 xx 0`
`:. Z = 36 =` Atomic number of `X` Atoms
Therefore, unknown product is `._(36)X^(88)`, i.e., `._(36)Kr^(88)`.
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Solved Example|18 Videos

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Ex6.1 Objective|15 Videos

  • NCERT BASED EXERCISE

    CENGAGE CHEMISTRY|Exercise Nuclear Chemistry (NCERT Exercise)|29 Videos

  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY|Exercise Archives Analytical And Descriptive|24 Videos

Similar Questions

Explore conceptually related problems

In a particular fission reaction, a ._92U^(235) nucleus captures a slow neutron. The fission products are three neutrons, a ._57La^(142) nucleus and a fission product ._ZX^A . What is the value of Z?

""_(92)U^(235) nucleus absorbs a neutron and disintegrates into ""_(54)Xe^(139) .""_(38)Sr^(94) and X. What will be the product X ?

""_(92)U""^(235) nucleus absorbes a neutron and disintegrate into ""_(54)Xe""^(139),""_(38)Sr""^(94) , and x neutrons x is

A neutron strikes a ""_(92)U^(235) nucleus and as a result ""_(36)Kr^(93) and ""_(56)Ba^(140) are produced with

In the neutron - induced fissioin reaction of ._(92)U^(235) one of the products if ._(37)Rb^(95), in this mode, another nuclide and three neutrons are also produced. Identify the nuclide.

In a neutron induced reaction ""_(92)^(235)U , the product obtained is ""_(37)^(95)Rb , three neutrons and an element (new nuclide) . The other new nuclide is

If ""_(92)U""^(235) nucleus absorbes neutron and disintegrates ""_(54)X""^(139).""_(38)Sr""^(95) and X. Then what will be the product X