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An atom has atomic mass 232 and atomic n...

An atom has atomic mass 232 and atomic number 90. During the course of disintegration, it emits 2 `beta`-particles and few `beta`-particles and few `alpha`-particles. The resultant atom has atomic mass 212 and atomic number 82. How many `alpha`-particles are emitted during this process?

Text Solution

Verified by Experts

Let the reaction is
`._(90)A^(232) rarr ._(82)B^(212) + x_(2)He^(4) + 2 ._(-1)e^(0)` ….(i)
Let `x` be the number of alpha particles emitted equate the atomic mass of the side of Eq. (i)
`232 = 212 + 4 x + 2 xx 0`
`:. X = (232 - 212)/(4) = 5`
Therefore, `5 alpha`-particles are emitted.
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