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During the transformation of .(c )X^(a) ...

During the transformation of `._(c )X^(a)` to `._(d)Y^(b)` the number of `beta`-particles emitted are
a. `d + ((a - b)/(2)) - c` b. `(a - b)/(c )`
c. `d + ((a - b)/(2)) + c` d. `2c - d + a = b`

A

a. `d + ((a - b)/(2)) - c`

B

b. `(a - b)/(c )`

C

c. `d + ((a - b)/(2)) + c`

D

d. `2c - d + a = b`

Text Solution

Verified by Experts

The correct Answer is:
a. `d + ((a - b)/(2)) - c`
a. For transformation of `._(c )X^(a) rarr ._(d)Y^(b) + x_(2)He^(4) + beta`
Number of `alpha`-particles emitted `= (a - b)/(4)`
Equating for atomic number on both sides, we get
`c = d + 2 ((a - b)/(2)) + beta (-1)`
or `beta = d + (a - b)/(2) - c`
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