In the radioacitve decay
`._(Z)X^(A) rarr ._(z + 1)Y^(A) rarr ._(z - 1)^(A - 4) rarr ._(z - 1)Z^(*A - 4)`
The sequence of emission is
a. `alpha, beta, gamma` b. `gamma, alpha, beta` c. `beta, alpha, gamma` c. `beta, gamma, alpha`

Explanation

To solve the problem of identifying the sequence of emissions during the radioactive decay process described, we can break it down step-by-step:

### Step 1: Analyze the first decay
The first decay is represented as:
\[ _{Z}X^{A} \rightarrow _{Z+1}Y^{A} \]
Here, the atomic number (Z) increases by 1, while the mass number (A) remains the same. This indicates that a beta particle (β) is emitted. In beta decay, a neutron is converted into a proton, resulting in an increase in the atomic number.
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