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One mole of X present in a closed vessel...

One mole of `X` present in a closed vessel undergoes decays as:
`._(Z)X^(A) rarr ._(Z - 2)Y^(A - 4) + (._(2)He^(4))`
What will be the volume of helium gas collected as `SATP` and `STP` (1 bar pressures, `273 K` temperature) after 20 days `(t_(1//2) "of" A = 10` days)?

Text Solution

Verified by Experts

`N = N_(0) ((1)/(2))^(n)`
`:. N = 1 ((1)/(2))^(2) = (1)/(4)` `[n = (T)/(t_(1//2)) = (20)/(10) = 2]`
Number of decayed moles `= 1 - (1)/(4) = (3)/(4)`
= Number of decayed mole of `A`
`= (3)/(4)`
Volume of helium at `STP` (1 atm, `298 K)`
`= (3)/(3) xx 24.4 = 18.3 L`
Volume of helium at `STP` (1 bar, `273 K)`
`= (3)/(4) xx 22.7 = 16.8 K`
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