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A piece of wood was found to have C^(14)...

A piece of wood was found to have `C^(14)//C^(12)` ratio 0.6 times that in a living plant. Calculate that in a living plant. Calculate the period when the plant died. (Half life of `C^(14) = 5760` years)?

Text Solution

Verified by Experts

We know that `t = (2.303 xx t_(1//2))/(0.693) "log" (N_(0))/(N)`
So `t = (2.303 xx 5760)/(0.693) "log" (1)/(0.6)`
`= (2.303 xx 5760)/(0.693) xx 0.2201`
`= 4213 "years"`
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