The activity of a nucleus is inversely proportional to its half of average life. Thus, shorter the half life of an element, greater is its radioactivity, i.e., greater the number of atomsd disintegrating per second. The relation between half life and average life is `t_(1//2) = (0.693)/(lambda) = tau xx 0.693`
or `tau = 1.44 t_(1//2)`
Mark the incorrect relation.

Options

A. `N_(0) = Ne^(lambda t)`
B. `tau = 1.44 t_(0.5)`
C. `N = N_(0) ((1)/(2))^(n)`
D. `t_(1//2) = 2.303 lambda "log" 2`

Answer

D

Explanation

`t = (2.303)/(lambda) "log" ((N_(0))/(N))`
For `t = (t)/(2) implies t_(1//2) = (2.303)/(lambda) "log" ((N_(0))/(N_(0)//2))`
`= (2.303)/(lambda) "log" 2`