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An element with molar mass 2.7 xx 10^(2)...

An element with molar mass `2.7 xx 10^(2) kg mol^(-1)` forms a `2.7 xx 10^(3) kg^(-3)`, what is the nature of the cubic unit cell?

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To determine the nature of the cubic unit cell based on the given molar mass and density, we can follow these steps: ### Step 1: Understand the given values - Molar mass (M) = \(2.7 \times 10^2 \, \text{kg/mol}\) - Density (d) = \(2.7 \times 10^3 \, \text{kg/m}^3\) ### Step 2: Use the formula for density of a cubic unit cell The formula for the density of a cubic unit cell is given by: \[ d = \frac{Z \cdot M}{N_A \cdot a^3} \] where: - \(d\) = density - \(Z\) = number of formula units per unit cell - \(M\) = molar mass - \(N_A\) = Avogadro's number (\(6.022 \times 10^{23} \, \text{mol}^{-1}\)) - \(a\) = edge length of the unit cell ### Step 3: Rearrange the formula to find Z We can rearrange the formula to solve for \(Z\): \[ Z = \frac{d \cdot N_A \cdot a^3}{M} \] ### Step 4: Calculate the edge length in meters Given that the edge length \(a\) is \(405 \, \text{pm}\) (picometers), we convert it to meters: \[ a = 405 \, \text{pm} = 405 \times 10^{-12} \, \text{m} \] ### Step 5: Calculate \(a^3\) Now, we calculate \(a^3\): \[ a^3 = (405 \times 10^{-12})^3 = 6.63 \times 10^{-29} \, \text{m}^3 \] ### Step 6: Substitute values into the equation for Z Now, substitute the values into the equation for \(Z\): \[ Z = \frac{(2.7 \times 10^3) \cdot (6.022 \times 10^{23}) \cdot (6.63 \times 10^{-29})}{(2.7 \times 10^2)} \] ### Step 7: Calculate Z Calculating \(Z\): \[ Z = \frac{(2.7 \times 10^3) \cdot (6.022 \times 10^{23}) \cdot (6.63 \times 10^{-29})}{(2.7 \times 10^2)} \approx 6 \] ### Step 8: Determine the nature of the cubic unit cell The value of \(Z\) indicates the number of atoms per unit cell. - If \(Z = 1\), it is a simple cubic unit cell. - If \(Z = 2\), it is a body-centered cubic (BCC) unit cell. - If \(Z = 4\), it is a face-centered cubic (FCC) unit cell. - If \(Z = 6\), it indicates a more complex structure, possibly a close-packed structure. Since we calculated \(Z \approx 6\), the nature of the cubic unit cell is likely a close-packed structure. ### Final Answer The nature of the cubic unit cell is a close-packed structure.

To determine the nature of the cubic unit cell based on the given molar mass and density, we can follow these steps: ### Step 1: Understand the given values - Molar mass (M) = \(2.7 \times 10^2 \, \text{kg/mol}\) - Density (d) = \(2.7 \times 10^3 \, \text{kg/m}^3\) ### Step 2: Use the formula for density of a cubic unit cell The formula for the density of a cubic unit cell is given by: ...
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CENGAGE CHEMISTRY-NCERT BASED EXERCISE-Nuclear Chemistry (NCERT Exercise)
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