The resistance of a conductivity cell contaning `0.001M KCl` solution at `298K` is `1500Omega`. What is the cell constant if conductivity of `0.001M KCl` solution at `298K` is `0.146 xx 10^(-3)S cm^(-3) S cm^(-1)`.

Answer

`0.219cm^(-1)`

Explanation

Cell constant `(G^(**))=(Conductivity(k))/(Conduct ance(G))=kxxR`
`=0.146xx10^(-3)Scm^(-1)xx1500ohm`
`=0.219cm^(-1)`