A solution of `Ni(NO_(3))_(2)` is electrolyzed between platium electrodes using a current of `5A` for `20 mi n`. What mass of `Ni` is deposited at the cathode ?

Answer

`1.825g`

Explanation

Quantity of electricity passed `=(5A)xx(20xx60s)`
`6000C`
Thus, `2F,i.e.,2xx96500C, ` deposit `Ni=1 mol=58.7g`
`:. 6000C ` will deposit `Ni=(58.7)/(2xx96500)xx6000g`
`=1.825g`