A reaction is second order with respect to a reaction. How is the rate of reaction affected if the
(a) doubled, (b) reduced to `1//2`?

Answer

`a. ` Rate becomes 4 times.
`b.` Rate becomes `1//4` times.

Explanation

`R rarr P or A rarr B`
`a.` Rate`=r_(1)=k[A]^(2)`
`r_(2)=k[2A]^(2)`
`r_(2)=4r_(1)`
Rate becomes 4 times.
`b.` `r_(1)=k[A]^(2)`
`r_(2)=k[(1)/(2)A]^(2)`
`(r_(2))/(r_(1))=[(1)/(2)]^(2)impliesr_(2)=(1)/(4)r_(1)`
Hence, rates becomes `(1)/(4)` times.