Calculate the binding energy per nucleon of `Li` isotope, which has the isotopic mass of `7.016 am u`. The individual masses of neutron and proton are `1.008665 am u` and `1.007277 am u`, respectively and the mass of electron `= 0.000548 am u`.

Answer

`5.6MeV`

Explanation

Nuclear binding energy `:` The nuclear binding energy can be defined in the following ways `:`
`a.` The energy needed to break a nucleus into its constituent nucleons `(` isolated protons and neutrons `0` is called nuclear binding energy.
`b.` The energy liberated when nucleons get packed together to form the nucleus is called nuclear binding energy.
`c.` The energy equivalent of mass defect `(DeltaE=Deltamc^(2))` in the formation of nucleus from protons and neutrons is called nuclear binding energy.
Num `:` Lithium nuclei `._(3)Li^(7)`
Number of protons `=3 `
Number of neutrons `=703=4`
Mass defect `=Deltam=[Zm_(H)+(A-Zm_(n)]-M`
`Deltam=3xx1.007277+4xx1.008665-7.016`
`=3.021831+4.03466-7.016`
`=7.056491-7.016`
`=0.040491 am u`
Total Be `=0.040491xx931.5`
`=37.717MeV`.
`BE//` nucleon`=(37.717)/(7)=5.6MeV`