fifty millilitre of a mixture of `CO` and `CH_4` was exploded with 85 ml of `O_2`. The volume of `CO_2` produced was 50 ml. Calculate the percentage composition of the gaseous mixture.

Explanation

let the volume of `CO=xml`
Volume of `CH_4=(50-x)ml`
`underset(xml)CO+(1)/(2)O_2rarrunderset(xml)(CO_2)` .(i)
`underset(50-x)CH_4+underset(2(50-x))+2O_2rarrunderset(50-x)CO_2+underset(-)2H_2O` .(ii)
Total volume of `O_2=(x)/(2)+2(50-x)=85`
`x=10ml`
Volume of `CO=10ml`
Volume of `CH_4=(50-10)=40ml`
percentage of `CO=(10xx100)/(50)=20%`
Percentage of `CH_4=(100-20)=80%`