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0.92 gm of an organic compound containin...

0.92 gm of an organic compound containing carbon, hydrogen, and oxygen was analysed by combustion method. The increase in the mass of the U-tube and the potash bulbs at the end of the operation was found to the 1.08 gm and 1.76 gm respectively. Determine the percentage composition of the compound.

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Increase in the mass of U-tube `=1.08gm`
Mass of water formed `=1.08gm`
since 18 gm of water contains 2 gm hydrogen
1.08 gm of water contains `(2)/(18)xx1.08gm` hydrogen
mass of the compound taken for analysis `=0.92gm`
Percentage of hydrogen `=(2)/(18)xx(1.08)/(0.92)xx100=13.04`
Increase in the mass of potash bulbs `=1.76gm`
mass of carbon dioxide formed `=1.76gm`
Since 44 gm of carbon dioxide contains 12 gm carbon
1.76 gm of carbon dioxide contains 12 gm carbon
1.76 gm of carbon contains `=(12)/(44)xx1.76gm` carbon
percentage of carbon `=(12)/(44)xx(1.76)/(0.92)xx100=52.17`
percentage of oxygen`=100-`(percentage of `C+`percent of H)
`=100-(52.17+13.04)`
`100-65.21=34.79`
Composition of the compound : `C=52.17%`,
`H=13.04%`,
`O=34.79%`
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