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7.5 ml of a gaseous hydrocarbon was expl...

7.5 ml of a gaseous hydrocarbon was exploded with 36 ml of `O_2`. On cooling the volume of gases was found to be 28.5 ml, 15 ml of which was absorbed by KOH and the rest was absorbed in a solution of alkaline pyrogallol. The formula of hydrocarbon is:

A

`C_2H_6`

B

`C_2H_4`

C

`C_3H_8`

D

`C_3H_6`

Text Solution

Verified by Experts

The correct Answer is:
B
`C_xH_y+(x+(y)/(4))O_2rarrxCO_2+(y)/(2)H_2O`
`7.5ml 7.5(x+(y)/(4))ml 7.5x ml _`
Volume of `CO_2=15ml`
`7.5x=15,x=2`
Volume of `O_2` (absorbed in pyrogallol) `=28.5-15`
`=13.5ml`
Volume of `O_2` (used) `=36-13.5=22.5ml`
`7.5(x+(y)/(4))=12.5`
Solving for `y`, putting `x=2,y=4`
Hence the formula `=C_2H_4`
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