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0.5 gm of an organic substance containin...

0.5 gm of an organic substance containing prosphorous was heated with sonc. `HNO_3` is the carius tube. The phosphoric acid thus formed was preciopitated with magnesia mixture `(MgNH_4PO_4)` which on ignition gave a residue of 1.0 gm of magnesium phrrophosphate `(Mg_2P_2O_7)`. The precentage of phosphorous in the organic compound is:

A

`55.85%`

B

`29.72%`

C

`19.18%`

D

`20.5%`

Text Solution

Verified by Experts

The correct Answer is:
A

`P+HNO_3toH_2PO_4underset((NH_4Cl+MgCl_2))toMgNH_4undersetunderset(Mg_2P_2O_7)(darrtriangle)(PO_4)`
Mw of `Mg_2P_2O_7=24xx2+31xx2+16xx7=222`
percentage of `P=(62)/(222)xx("weight of "Mg_2P_2O_7)/("weight of compound")xx100`
`=(62)/(222)=(1.0)/(0.5)xx100=55.85%`
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