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A compound contains 38.8%C,16%H, and 45....

A compound contains `38.8%C,16%H`, and `45.2%N` The formula of the compound would be

A

`CH_3NH_2`

B

`C_2H_5CN`

C

`CH_3CH`

D

`CH_2(NH_2)_2`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(C,,H,,N),((38.8)/(12),,(16)/(1),,(45.2)/(14)),(3.23,,16,,3.2),(1,,5,,1):}`
`MF=CH_5N=CH_3NH_2`
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