An organic compound on analysis gave `C=42.8%`, `H=720%`, and`N=50^` volume of 1 gm of the compoun was found to be 200 ml at STP. Molecular formula of the compound is:

Options

A. `C_4H_8N_4`
B. `C_(16)H_(32)N_(16)`
C. `C_(12)H_(24)N_(12)`
D. `C_2H_4N_2`

Answer

A

Explanation

`{:(C,,H,,N),((42.8)/(12),,(7.2)/(1),,(50)/14),(3.56,,7.2,,3.57),(1,,2,,1):}`
`EF=CH_2N`
`200ml=1gm`
`22400ml=(22400)/(200)=112gm`
`M.W.=112gm`
`E.F.W.=CH_2N=12+2+14=28`
`n=(M.W.)/(E.F.W.)=(112)/(28)=4`
`MF=C_4H_8N_4`