Home
Class 11
CHEMISTRY
(a). If both (A) and (R) are correct and...

(a). If both (A) and (R) are correct and (R) is the correct explanation for (A).
(b). If both (A) and (R) are correct and (R) is the correct explanation for (A).
(c). If (A) is correct and (R) is incorrect.
(d). If (A) is incorrect and (R) is correct. ltbr. (e). If both (A) and (R) are incorrect.
Q. Assertion (A): Hydroxylamine `(NH_2OH)` contains N, and hence gives prussian blue colour in lassaigne's test.
Reason (R): Hydroxylamine does not contain C, so with `Na` metal. `CN^(c-)` ion is not formed.

Text Solution

Verified by Experts

The correct Answer is:
D
(A) is wrong it does not give positve test for N since it does not contain C So `CN^(c-)` ion is not obtained which is an essential condition for the test for N. But (R) is correct.
Promotional Banner

Topper's Solved these Questions

  • PURIFICATION OF ORGANIC COMPOUNDS AND QUALITATIVE AND QUANTITATIVE ANALYSIS

    CENGAGE CHEMISTRY|Exercise Single Correct Answer Type|40 Videos

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY|Exercise Exercises (Archives )Subjective|4 Videos

  • REDOX REACTIONS

    CENGAGE CHEMISTRY|Exercise Archives (Integers)|1 Videos

Similar Questions

Explore conceptually related problems

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): Concentration of H_(2)O_(2) is expressed in volume Reason (R): Volume strength = normality xx5.6

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): H_(3)PO_(2) is mono basic acid. Reason (R): Two H-atoms are attached to pghosphorous (P).

(a). If both (A) and (R) are correct and (R) is the correct explanation for (A). (b). If both (A) and (R) are correct and (R) is the correct explanation for (A). (c). If (A) is correct and (R) is incorrect. (d). If (A) is incorrect and (R) is correct. ltbr. (e). If both (A) and (R) are incorrect. Q. Assertion (A): Benzene (boiling point 353K) and methanol (boiling point 338K) are separated by simple distillation. Reason (R): Fractional distillation is used to separate two liquids from their mixture when their boiling points differ by 20^@ or so.

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): IN the reaction 2S_(2)O_(3)^(2-)+I_(2)toS_(4)O_(6)^(2-)+2I^(ɵ) Reason (R): During oxidation loss of electron takes place.

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): In the titration of strong acid and strong base, phenolphthalein is used as suitable indocator. Reason (R): IN the titration of strong acid and strong base, the equivalence points lies is the pH range of (3.0-10.5) and phenolphthalein have pH range of (8.0-9.8) .

(a). IF both (A) and (R) are correct and (R) is the correct explanation of (A). (b). If both (A) and (R) are correct but (R) is not the correct explanation of (A). (c). If (A) is correct, but (R) is incorrect. (d). If (A) is incorrect, but (R) is correct. ltbr. (e) if both (A) and (R) are incorrect. Q. Assertion (A): When gaseous hydrocarbon are completely burnt in eudiometer tube with excess of O_(2) and after cooling there is a contraction in the volume of gases. Reason (R): The volume of H_(2)O is not considered.