What is the equivalent resistance across the points A and B in the circuit given below :–

Options

A. `8Omega`
B. `12Omega`
C. `16Omega`
D. `32Omega`

Answer

A

Explanation

`rArr 10Omega & "2.5 are in parallel"`
so `R_("eg")=(10xx2.5)/(10+2.5)=(25)/(12.5)=2Omega`
then `2Omega &10` are in series
so `R_("eg")=10+2=12Omega`
Now `12Omega||12Omega rArr "so"_("Reg")=6Omega`
then `6Omega&10Omega` are in series
so `R_("eg")=16& "then "16Omega||16Omega`
so Reg = `8Omega`