Two coils of 10 turns each are arranged ...

Two coils of 10 turns each are arranged such that mutual inductance between them is 150 mH. Magnetic flux linked through one coil when 2 ampere current will flow in another coil:-

`1xx10^(-3)Wb`

`10xx10^(-3)Wb`

`20xx10^(-3)Wb`

`30xx10^(-3)Wb`

Text Solution

Verified by Experts

The correct Answer is:

By `N_(1)varphi_(1)=MI_(2) rArr varphi_(1)=(MI_(2))/(N_(1))`
`=(150xx10^(-3)xx2)/(10)=0.03`

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