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A particle is projected horizontally wit...

A particle is projected horizontally with a speed of `(40)/(sqrt3)m//s`, from some height `t = 0`. At what time its velocity makes `60^(@)` angle with initial velocity.
`(g=10m//s^(2))`

A

4s

B

2s

C

5s

D

3s

Text Solution

Verified by Experts

The correct Answer is:
A
`tan alpha=(v_(y))/(v_(x)),sqrt3=("gt")/(((40)/(sqrt3))), sqrt3=(g t sqrt3)/(40 t=4s`
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