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A particle starts with constant angular ...

A particle starts with constant angular acceleration of `"2 rad/s"^(2)` in a circle of radius 4m. Find angle between net acceleration and radial acceleration after 2 s :-

A

`theta=tan^(-1)((1)/(8))`

B

`theta=tan^(-1)((1)/(4))`

C

`theta=tan^(-1)((1)/(2))`

D

`theta=tan^(-1)((1)/(16))`

Text Solution

Verified by Experts

The correct Answer is:
A

`vec(alpha)=2"rad/s"`
`r=4m`
`omega=0+2(2) rArr omega=4"rad/s"`
`a_("cp")=omega^(2)r=64`
`a_(t)=alphar=8`
`tan alpha=((a_(t))/(a_(r))), alpha=tan^(-1)((1)/(8))`
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