Complete the following activity to find the natural numbers between 1 and171 which are divisibleby 5.
The natural numbers between 1 and171 divisible by 5 are 5,10,15, …,170.
Here, `a = square, d = square, t_(n) = 170`
`t_(n) = a + ( n -1) d `
`:. 170 = 5 + ( n -1) xx 5 `
` :. 170 = square `
` n = square `

Explanation

To find the natural numbers between 1 and 171 that are divisible by 5, we can follow these steps:

### Step 1: Identify the first term (a) and the common difference (d)
The first natural number greater than 1 that is divisible by 5 is 5. Therefore, we have:
- \( a = 5 \)
- The common difference \( d = 5 \) (since the numbers are in an arithmetic progression).

### Step 2: Identify the last term (t_n)
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