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In DeltaABC, AC=BC and /ACB=90^(@) then ...

In `DeltaABC`, `AC=BC` and `/_ACB=90^(@)` then prove `AB^(2)=2AC^(2)`

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`AC=CB`……(Given)…..`(1)`
In `DeltaACB`,
`/_ACB=90^(@)` ……..(Given)
`:.` by Pythagoras theorem, `AB^(2)=AC^(2)+CB^(2)`
`:.AB^(2)=AC^(2)+AC^(2)`…….[Fromn`(1)`]
`:.AB^(2)=2AC^(2)`
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