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Two circles intersect each other in points A and B. Seg AB is the chord of both the circles . Point C is in the exterior point of both the circles on the line AB. From the point C tangents are drawn to the circles touching at M and N as shown. Completely the following to prove CM= CN.
Proof `:`
`CM^(2) = CA xx square ` ....( `square `) ....(1)
`CN^(2) = square xx CB ` ...(Tangent secant segment property ) ....(2)
`:.` From (1) and (2),
`CM^(2) = square `
`:. CM = CN `

Text Solution

Verified by Experts

The correct Answer is:
CB,Tangent secant segment property , CA , `CN^92)`
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