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Delta ABC ~ Delta LMN. In Delta ABC, AB ...

`Delta ABC ~ Delta LMN`. In `Delta ABC, AB = 5.5 cm`, BC = 6 cm, CA = 4.5 cm. If MN = 4.8 cm then construct `Delta ABC` and `Delta LMN`

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`Delta ABC ~ Delta LMN` ….. (Given)
`:. (AB)/(LM) = (BC)/(MN) = (AC)/(LN)` …. (c.s.s.t)
`:. (5.5)/(LM) = (6)/(4.8) = (4.5)/(LN)`
`:. (5.5)/(LM) = (6)/(4.8)`
`:. LM = (5.5 xx 4.8)/(6)`
`:. LM = 4.4 cm`
similarly `(6)/(4.8) = (4.5)/(LN)`..... [from (i)]
`:. LN = (4.8 xx 4.5)/(6)`
`:. LN = 0.8 xx 4.5`
`:. LN = 3.6 cm`

One mark of construction of each triangle
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