State the expression for the MI of a thin ring about a transverse axis through its centre. Hence, derive the expression for the MI of the ring about its tangent perpendicular to the plane.

Radius of gyration of a ring about a transverse axis passing through its centre is

State the expression for the moment of inertia of a thin uniform disc about an axis perpendicular to its plane and through its centre. Hence deduce the expression for its moment of inertia about a tangential axis perpendicular to its plane.

Derive an expression for moment of inertia of a thin circular ring about an axis passing through its centre and perpendicular to the plane of the ring.

Assuming the expression for the MI of a unifrom solid sphere about its diameter, obtain the expression for its moment of inertia about a tangent.

If the moment of inertia of a ring about transverse axis passing through its centre is 6 kg m^(2) , then the M.I. about a tangent in its plane will be

A thin wire of mass m and length l is bent in the form of a ring . Moment of inertia of that ring about an axis passing through its centre and perpendicular to its through its centre and perpendicular to its plane is

If I_(1) is the moment of inertia of a thin rod about an axis perpendicular to its length and passing through its centre of mas and I_(2) is the moment of inertia of the ring about an axis perpendicular to plane of ring and passing through its centre formed by bending the rod, then