निम्न में से प्रत्येक को सरल कीजिए।
` (25)^(-1//3)xxroot3(16)`

Explanation

`(i)` यहाँ `(25)^(-1//3)xxroot3(16)=(25)^(-1//3)xx(16)^(1//3)=((16)^(1//3))/((25)^(1//3))=((16)/(25))^(1//3)`
`=((2^(3)xx2)/(5^(2)))^(1//3)=((2^(3)xx2xx5)/(5^(2)xx5))^(1//3)=((2^(3))/(5^(3))xx10)^(1//3)`
`=((2^(3))/(5^(3)))^(1//3)xx(10)^(1//3)=[((2)/(5))^(3)]^(1//3)xx10^(1//3)=(2)/(5)xx10^(1//4)`
`(ii)` यहाँ
`(sqrt(4))^(-7)(sqrt(2))^(-5)=(4^(1//2))^(-7)(2^(1//2))^(-5)=(1)/((4^(1//2))^(7)(2^(1//2))^(5))=(1)/([(2^(2))^(1//2)]^(7)(2^(1//2))^(5))`
`=(1)/(2^(7)xx2^(5//2))=(2^(1//2))/(2^(7)xx2^(1//2)xx2^(5//2))`
`=(2^(1//2))/(2^(7)xx2^((1//2+5//2)))=(2^(1//2))/(2^(7)xx2^(3))=(2^(1//2))/(2^(10))`