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A particle executing SHM. The phase diff...

A particle executing SHM. The phase difference between velocity and displacement is

A

0

B

`(pi)/(2)`

C

`pi`

D

`2pi`

Text Solution

Verified by Experts

The correct Answer is:
B

Let the displacement of a particle executing
SHM at any instant t is, `x=Acosomegat`
Velocity, `v=-Aomegasinomegat=Aomegacos(omegat+(pi)/(2))`
Phase of displacement, `phi_(1)=omegat`
Phase of velocity, `phi_(2)=(omegat+(pi)/(2))`
`therefore`Phase difference `=phi_(2)-phi_(1)=omegat+(pi)/(2)-omegat=(pi)/(2)`
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