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Using the data given below: E(Cr(2)O(7...

Using the data given below:
`E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V`
`E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V`
In which option the order of reducing power is correct?

A

`Cr^(3+) lt Cl^(-) lt Mn^(2+) lt Cr `

B

`Mn^(2+) lt Cl^(-) lt Cr^(3+) lt Cr`

C

`Cr^(3+) lt Cl^(-) lt Cr_2O_7^(2-) lt MnO_4^-`

D

`Mn^(2+) lt Cr^(3+) lt Cl^(-) lt Cr`

Text Solution

Verified by Experts

The correct Answer is:
B
Lower the reduction potential, higher is the reducing power.
`Mn^(2+) lt Cl^(-) lt Cr^(3+) lt Cr`
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