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Lambda((m)(NH(4)OH))^(@) is equal to...

`Lambda_((m)(NH_(4)OH))^(@)` is equal to

A

`Lambda_(m(NH_4OH))^@ + Lambda_(m(NH_4Cl))^@-Lambda_(m(HCl))^@`

B

`Lambda_(m(NH_4Cl))^@+Lambda_(m(NaOH))^@-Lambda_(m(NaCl))^@`

C

`Lambda_(m(NH_4Cl))^@+Lambda_(m(NaCl))^@-Lambda_(m(NaOH))^@`

D

`Lambda_(m(NaOH))^@+Lambda_(m(NaCl))^@-Lambda_(m(NH_4Cl))^@`

Text Solution

Verified by Experts

The correct Answer is:
B
`Lambda_(m(NH_4Cl))^@+Lambda_(m(NaOH))^@-Lambda _(m(NaCl))^@`
`Lambda_(m(NH_4^+))^@+Lambda_(m(Cl^-))^@+Lambda_(m(Na^+))^@+Lambda_(m(OH^-))^@-Lambda_(m(Na^+))^@-Lambda_(m(Cl^-))^@`
`=Lambda_(m(NH_4^+))^@+Lambda_(m(OH^-))^@=Lambda_(m(NH_4OH))^@`
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