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Ni(CO)(4) is...

`Ni(CO)_(4)` is

A

tetrahedral

B

square planar

C

linear

D

octahedral .

Text Solution

Verified by Experts

The correct Answer is:
C
In `[Ni(CO)_(4)]` , oxidation state of Ni = 0
`Ni : 3d^(8) 4s^(2) : `

`sp^(3)` hybridisation has tetrahedral shape .
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