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The colour of the coordination compounds...

The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light of the visible region, for the complexes, `[Co(NH_(3)_(6)]^(3+). [Co(CN)_(6)]^(3+). [Co(H_(2)O)_(6)]^(3+)`

A

`[Co(CN)_(6)]^(3-) gt [Co(NH_(3))_(6)]^(3+) gt [Co(H_(2)O)_(6)]^(3+)`

B

`[Co(NH_(3))_(6)]^(3+) gt [Co(H_(2)O)_(6)]^(3+) gt [Co(CN)_(6)]^(3-)`

C

`[Co(H_(2)O)_(6)]^(3+) gt [Co(NH_(3))_(6)]^(3+) gt [Co(CN)_(6)]^(3-)`

D

`[Co(NH_(3))_(6)]^(3+) gt [Co(CN)_(6)]^(3-) gt [Co(H_(2)O)_(6)]^(3+)`

Text Solution

Verified by Experts

The CFSE of the ligands is in the order :
`H_(2)O lt NH_(3) lt CN^(-)`
Hence , excitation energies are in the order .
`[Co(H_(2)O)_(6)]^(3+) lt [Co(NH_(3))_(6)]^(3+) lt [Co(CN)_(6)]^(3-)`
From the relation ` E = (hv)/(lambda) implies E prop (1)/(lambda)`
The order of absorption of wavelength of light in the visible region is :
`[Co(H_(2)O)_(6)]^(3+) gt [Co(NH_(3))_(6)]^(3+) gt [Co(CN)_(6)]^(3-)`
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